Where did I take that photo?

I couldn’t find anyone extracting out the geolocation geotagging EXIF data from their photographs so they could pull it up on something like Google Maps.  There are stand-alone programs with embedded maps, but the bits and bobs lying around on the average system ought to be enough to just generate a URL to a mapping website.  The following bash script echoes the  URL that geolocates your JPEG.  Because my camera doesn’t emit it, I couldn’t be bothered dealing with the seconds part of a location, but I did detect that you don’t have a camera the same as mine.  Drop a line if you’ve used this and fixed it.

#!/bin/bash
# emit a hyperlink to google maps for the location of a photograph
declare Seconds=""
Seconds=`exif -m --ifd=GPS --tag=0x02 $1 | grep -oP "[\d|\d\.]+$"`
if (( $Seconds=='0' ))
then
  Seconds=`exif -m --ifd=GPS --tag=0x04 $1 | grep -oP "[\d|\d\.]+$"`
fi
if (( $Seconds!='0' ))
then
  echo
  echo "Script does not support seconds being specified"
  exit
fi
echo -n "https://maps.google.com.au/?q="
declare NorthSouth=`exif -m --ifd=GPS --tag=0x01 $1`
if [ "$NorthSouth" == "S" ] 
then
  echo -n "-"
fi
echo -n `exif -m --ifd=GPS --tag=0x02 $1 | grep -oP "^[\d|\d\.]+"`
echo -n "%20"
echo -n `exif -m --ifd=GPS --tag=0x02 $1 | grep -oP "(?<= )[\d|\d\.]+,"`
declare EastWest=`exif -m --ifd=GPS --tag=0x03 $1`
if [ "$EastWest" == "W" ]
then
  echo -n "-"
fi
echo -n `exif -m --ifd=GPS --tag=0x04 $1 | grep -oP "^[\d|\d\.]+"`
echo -n "%20"
echo -n `exif -m --ifd=GPS --tag=0x04 $1 | grep -oP "(?<= )[\d|\d\.]+(?=,)"`
echo

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